Two tourist buses start from the same point and move along two roads at right angles at speeds of 48 km/h and 36 km/h, respectively. The distance between the buses after 15 seconds is _________.
Answer & explanation
Correct answer: option 3
x km/h = x × \(\frac{5}{18}\) m /sec
Speed of Bus A = 48 km/h
= 48× \(\frac{5}{18}\) = \(\frac{40}{3}\) m/s
Speed of bus B = 36 km/h
= 36 × \(\frac{5}{18}\) = 10 m/sec
Bus A travel distance in 15 sec
Distance = \(\frac{40}{3}\) x 15 = 200 m
Bus B travel distance in 15 sec
Distance = 10 x 15 = 150 m
as the two road is at right angle, so
Let Height = 200 m
Base = 150 m
By Pythagoras theorem
Hypotenuse^2 = Base^2+ Height^2
Distance between two buses = 200^2 + 150^2
= 40000 + 22500
Hypotenuse^2 = 62500 = 250m