Two tourist buses start from the same point and move along two roads at right angles at speeds of 48 km/h and 36 km/h, respectively. The distance between the buses after 15 seconds is _________.

250 m

x km/h = x × \(\frac{5}{18}\) m /sec

Speed of Bus A = 48 km/h

= 48× \(\frac{5}{18}\)  =  \(\frac{40}{3}\) m/s

 Speed of bus B = 36 km/h

= 36 × \(\frac{5}{18}\)  = 10 m/sec

Bus A travel distance in 15 sec

 Distance = \(\frac{40}{3}\) x 15 = 200 m

Bus B travel distance in 15 sec

 Distance = 10 x 15 = 150 m

as the two road is at right angle, so

 Let Height = 200 m

 Base = 150 m

By Pythagoras theorem

Hypotenuse^2 = Base^2+ Height^2

 Distance between two buses = 200^2 + 150^2

= 40000 + 22500

Hypotenuse^2 = 62500 = 250m