Two condensers are once connected in parallel and then in series. If the equivalent capacitance in two cases are 16 F and 3F respectively, then capacity of each condenser is
Answer & explanation
Correct answer: option 2
Let C1 and C2 be the individual capacitance
then C1 + C2 = 16 . . . .(i)
$\frac{C_1 C_2}{C_1+C_2}$ = 3 . . . . (ii)
From (i) and (ii) C1 = 12 F, C2 = 4F