Practicing Success
Practicing Success
CUET Preparation Today
The period of oscillation of a freely suspended bar magnet is 4 second. If it is cut into two equal parts length wise then the time period of each part will be- |
4 Sec 2 Sec 0.25 Sec 0.5 sec |
4 Sec |
$ T = 2\pi \sqrt {\frac{I}{MB}} = 2\pi \sqrt {\frac{ml^2}{12mlB}} = 4 sec$ |
