Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Application of Integrals

Question:

Find the area of the intersected curve formed by \(y^{2}=2x+1\) and \(x-y-1=0\)

Options:

\(4\) sq. units

\(4\frac{3}{4}\) sq. units

\(4\frac{2}{4}\) sq. units

None of these

Correct Answer:

None of these

Explanation:

Area = $\int_{-1}^{3}\left[(y+1)-\left(\frac{y^{2}}{2}-\frac{1}{2}\right)\right]dy$

$=\frac{16}{3}$ sq. units