Find the area of the intersected curve formed by \(y^{2}=2x+1\) and \(x-y-1=0\)
Answer & explanation
Correct answer: option 4
Area = $\int_{-1}^{3}\left[(y+1)-\left(\frac{y^{2}}{2}-\frac{1}{2}\right)\right]dy$
$=\frac{16}{3}$ sq. units
Find the area of the intersected curve formed by \(y^{2}=2x+1\) and \(x-y-1=0\)
Correct answer: option 4
Area = $\int_{-1}^{3}\left[(y+1)-\left(\frac{y^{2}}{2}-\frac{1}{2}\right)\right]dy$
$=\frac{16}{3}$ sq. units