If $\sin θ+cosec\,θ = 2$, then what is the value of $\sin^2θ + cosec^2\,θ$? |
4 8 2 16 |
2 |
sinθ + cosec θ = 2 { we know, sinθ = \(\frac{1}{sinθ}\) } sinθ + \(\frac{1}{sinθ}\) = 2 On squaring both side , ( sinθ + \(\frac{1}{sinθ}\) )² = 2² sin²θ + \(\frac{1}{sin²θ}\) + 2 = 4 sin²θ + \(\frac{1}{sin²θ}\) = 2 |