The current I flowing in the circuit is:

2.4 A

The correct answer is Option (2) → 2.4 A

$I=I_1+I_2=I_4+I_3+I_2$  ...(1)

$I_1=I_4+I_3$   ...(2)

By kirchoff voltage law,

$ΔV=0$

$12-4I_1-(I_4+I_2)3=0$   ...(3)

$12-12I_2-(I_4+I_2)3=0$   ...(4)

$12-4I_1-6I_3=0$   ...(5)

Consider eq. (5)

$12-4I_1=6I_3$

Putting this in eq. (3)

$6I_3=(I_4+I_2)3$

$2I_3=I_4+I_2$

Substituting this in eq. (1)

$I=2I_3+I_3=3I_3$

∴ On solving above equations

$I=3I_3$

$=3×0.8$

$=2.4A$