What is the value of $ \frac{tanA - sinA}{tanA +sinA}$?
Answer & explanation
Correct answer: option 3
$ \frac{tanA - sinA}{tanA +sinA}$
Taken A = 45°
= $ \frac{1 - \frac{1}{\sqrt{2}}}{1 +\frac{1}{\sqrt{2}}}$
= 1 - $(\frac{1}{\sqrt{2}})^2$ (using (a+b)(a-b) =a²-b²)
= 1 - $\frac{1}{2}$
= $\frac{1}{2}$
This is satisfied by option#3 $\frac{secA - 1}{secA+ 1}$