What is the value of $ \frac{tanA - sinA}{tanA +sinA}$?

1  $\frac{secA + 1}{secA-1}$  $\frac{secA - 1}{secA+ 1}$ sec A

$\frac{secA - 1}{secA+ 1}$

$ \frac{tanA - sinA}{tanA +sinA}$ Taken A = 45° = $ \frac{1 - \frac{1}{\sqrt{2}}}{1 +\frac{1}{\sqrt{2}}}$ = 1 - $(\frac{1}{\sqrt{2}})^2$      (using (a+b)(a-b) =a²-b²) = 1 - $\frac{1}{2}$ = $\frac{1}{2}$ This is satisfied by option#3 $\frac{secA - 1}{secA+ 1}$