The expression for the equivalent capacitance of the system shown above is:

None of the above

The three capacitors are in parallel.

∴ Equivalent capacitance

C = C₁ + C₂ + C₃

$=\frac{\varepsilon_0 A}{d}+\frac{\varepsilon_0 A}{2 d}+\frac{\varepsilon_0 A}{3 d}$

$=\frac{\varepsilon_0 A}{d}\left(1+\frac{1}{2}+\frac{1}{3}\right)=\frac{11}{5} . \left(\frac{\varepsilon_0 A}{d}\right)$