The expression for the equivalent capacitance of the system shown above is:
Answer & explanation
Correct answer: option 4
The three capacitors are in parallel.
∴ Equivalent capacitance
C = C1 + C2 + C3
$=\frac{\varepsilon_0 A}{d}+\frac{\varepsilon_0 A}{2 d}+\frac{\varepsilon_0 A}{3 d}$
$=\frac{\varepsilon_0 A}{d}\left(1+\frac{1}{2}+\frac{1}{3}\right)=\frac{11}{5} . \left(\frac{\varepsilon_0 A}{d}\right)$