Practicing Success
When ${ }_{92} U^{235}$ undergoes fission, 0.1% of its original mass is changed into energy. How much energy is released if 1 kg of ${ }_{92} U^{235}$ undergoes fission |
$9 \times 10^{10} \mathrm{~J}$ $9 \times 10^{11} \mathrm{~J}$ $9 \times 10^{12} \mathrm{~J}$ $9 \times 10^{13} \mathrm{~J}$ |
$9 \times 10^{13} \mathrm{~J}$ |
$E=\Delta m c^2, \Delta m=\frac{0.1}{100}=10^{-3} \mathrm{~kg}$ ∴ $E=10^{-3} \times\left(3 \times 10^8\right)^2=10^{-3} \times 9 \times 10^{16}=9 \times 10^{13} \mathrm{~J}$ |