Practicing Success
Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 0.3 and 0.2 respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by second plane is |
0.2 0.7 0.06 0.14 |
0.14 |
Let $A_i (i=1, 2)$ denote the event that ith plane hits the target. Clearly, $A_1$ and $A_2$ are independent events. Required probability $=P(\overline{A_1} ∩ A_2)$ $= P(\overline{A_1}) P(A_2) = 1(1-0.3) ×0.2 = 0.14$ |