If $sin^4x + sin^2x = 1$, then what is the value of $cot^4x + cot^2x$ ?

-2 2 -1 1

1

We are given that,  $sin^4x + sin^2x = 1$  $sin^4x  = 1 - sin^2x$ { we know, sin²x + cos²x = 1 }  $sin^4x  = cos^2x$ sin²x = \(\frac{cos²x}{sin²x}\) sin²x = cot²x    -----(1) Now, $cot^4x + cot^2x$ By using equation 1. = sin4 x + sin²x  = 1          { given }