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Home/Practice questions/Physics
PhysicsRay Optics

Answer & explanation+

Correct answer: option 1

$\text{Apparent depth of water } d_A = d_R \frac{\mu_1}{\mu_2}$

$\text{Rate of change od apparent depth} \frac{\Delta d_A}{\Delta t} = \frac{\Delta d_R}{\Delta t}\frac{\mu_1}{\mu_2}$

$\frac{\Delta d_R}{\Delta t} = \frac{\Delta V}{\Delta t}$

$\Rightarrow  \frac{\Delta d_A}{\Delta t} = \frac{\Delta V}{\Delta t}\frac{\mu_1}{\mu_2}= \pi R^2 x \frac{\mu_1}{\mu_2}$

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