CUET Preparation Today
In a coil, an increase in current from 5 A to 10 A in 100 ms induces an induced emf of 100 V. The self inductance of the coil is: |
2 H 10 H 20 H 2000 H |
2 H |
The correct answer is Option (1) → 2 H Using Faraday's law of induction, $ε=-L\frac{ΔI}{Δt}$ $⇒L=\frac{εΔt}{ΔI}=\frac{100V×0.15}{5A}=\frac{10Vs}{5A}=2H$ |
