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The corecivity of a bar magnet is 100 A/m. It is to be demagnetised by placing it inside a solenoid of length 100 cm and number of turns 50. The current flowing the solenoid will be- |
4A 2A 1A Zero |
2A |
$H = nI$ $ I = \frac{H}{n} = \frac{100}{50} = 2A$ |
