Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Compound Interest

Question:

Ramesh borrowed Rs.3600 at a certain rate of interest C.I. and the sum grows to Rs.4624 in 2 years. What is the rate of interest in percentage?

Options:

15.3

14.3

13.3

12.3

Correct Answer:

13.3

Explanation:

The Formula that we used here is -

Amount = P$(1 \;+\; \frac{R}{100})^t$

Compound Interest = Amount - Principal

4624 = 3600 $(1 \;+\; \frac{R}{100})^2$

\(\frac{4624}{3600}\) = $(1 \;+\; \frac{R}{100})^2$

\(\frac{68}{60}\) = 1 + \(\frac{R}{100}\)

\(\frac{68}{60}\) - 1 = \(\frac{R}{100}\)

\(\frac{8}{60}\) = \(\frac{R}{100}\)

R = 13.3%