The smaller of the areas enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is
Answer & explanation
Correct answer: option 2
Circle in Ist quadrant
→ $y = \sqrt{4 - x^2}$
area of portion = $\frac{\text{area of circle}}{4} - \text{area of triangle}$
$=\frac{\pi \times 4}{4}-\frac{1}{2} \times 2 \times 2$
$=\pi-2$
Option: 2