CUET Preparation Today
The frequency of revolution of an electron revolving in a circular path in a magnetic field of $7.8 × 10^{-4} T$ will be (Take $e = -1.6 × 10^{-19} C; m_e = 9.1 × 10^{-31} kg; \pi = 22/7$) |
42 MHz 21.8 MHz 220 MHz 46 MHz |
21.8 MHz |
The correct answer is Option (2) → 21.8 MHz |
