A person goes to his office by scooter at the speed of 80 km/hr and reaches 60 minutes earlier. If he goes at the speed 50 km/hr, then he reaches 48 minutes late. What will be the speed of the scooter to reach on the usual time?
Answer & explanation
Correct answer: option 3
Let the actual time taken = T hours
And, speed of scooter to reach the office on time be x .
Distance = speed × time
According to question,
80(T - 60) = 50(T + 48)
8T - 480 = 5T + 240
3T = 720
T = 240 min
= 4 hours
With 80km/h speed he reaches in 3 hours
So , Distance = 80 × 3 = 240 km
Usual speed = \(\frac{240}{4}\)
= 60 km/h