The resistance of a wire of uniform diameter d and length l is R. The resistance of the another wire of the same material but diameter 2d and length 4l will be |
2R R R/2 R/4 |
R |
$ R = \frac{\rho l}{A}$ $ \frac{R'}{R} = \frac{l'}{l} \frac{A}{A'} = 4\times \frac{1}{4} = 1$ $\Rightarrow R'= R$ |