What is the total electric flux coming out from a closed surface enclosing an alpha particle? Given \( e = 1.6\times10^{-19}\,\mathrm{C} \)
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( \displaystyle\phi = \frac{2e}{\varepsilon_0} \)
By Gauss’s law, the total flux through any closed surface depends only on the charge enclosed: \( \phi = q_{\mathrm{enc}}/\varepsilon_0 \).
An alpha particle is a helium nucleus: 2 protons and 2 neutrons. Only the protons are charged, so
\( q_{\mathrm{enc}} = +2e \)
\( \displaystyle \phi = \frac{2e}{\varepsilon_0} \)