What is the total electric flux coming out from a closed surface enclosing an alpha particle? Given $e=1.6 × 10^{-19} C$
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\phi=\frac{2e}{ε_0}$
According to Gauss law,
$\phi=\frac{q_{enclosed}}{ε_0}$
Charge enclosed in an alpha particle, $Q_{enc}=+2e$
$∴\phi=\frac{2e}{ε_0}$