CUET Preparation Today
What is the total electric flux coming out from a closed surface enclosing an alpha particle? Given $e=1.6 × 10^{-19} C$ |
$\phi=\frac{e}{ε_0}$ $\phi=\frac{e}{2ε_0}$ $\phi=\frac{4e}{ε_0}$ $\phi=\frac{2e}{ε_0}$ |
$\phi=\frac{2e}{ε_0}$ |
The correct answer is Option (4) → $\phi=\frac{2e}{ε_0}$ According to Gauss law, $\phi=\frac{q_{enclosed}}{ε_0}$ Charge enclosed in an alpha particle, $Q_{enc}=+2e$ $∴\phi=\frac{2e}{ε_0}$ |
