How much charge is required for the reduction of 1 mol of MnO4¯ to Mn2+?

1 F 5 F 3 F 6 F

5 F

\(MnO_4^− + 8H^+ + 5e^− ————→ Mn^{2+} + 4H_2O\) Number of electrons = 5 we know, 1 mole of electron = 1 Faraday 5 moles of electron = 5 Faraday