What will be the compound interest when ₹13824 is deposited in a bank at \(4\frac{1}{6}\)% per annum compounded annually for 3 years?

₹1750 ₹1801 ₹1820 ₹1790

₹1801

CI for 3 years =  P (1+ \(\frac{25}{6 \times 100}\))³ - P                      = 13824[ (\(\frac{25}{24}\))³ - 1]                      = 13824 \(\frac{1801}{13824}\)                                     = 1801