Menu and Daya travel from point A to B, a distance of 105 km, at speeds of 10 km/h and 25 km/h, respectively. Daya reaches point B first and returns immediately and meets Menu at point C. Find the distance from point A to point C.
Answer & explanation
Correct answer: option 2
Speed of Menu = 10 km / hr.
Speed of Daya = 25 km/ hr.
Total distance b/w A & B = 105 km
Daya covered 105 km and returns immediately.
Daya reaches the other end of B ie
the time taken to travel 105 km is = \(\frac{105}{25}\) = 4.2 hours
So , in 4.2 hours distance traveled by Menu= 10 x 4.2 = 42 km.
Remaining distance to be covered by Menu = 105 – 42 = 63 kms.
As , both now travel in opposite direction . So relative speed 25 + 10 = 35 km/h
So, the time taken to meet each other = \(\frac{63}{35}\) =1.8 hrs
Distance covered by Menu in 1.6 hours is 10 x 1.8 = 18 km
Now the distance AC is 42 + 18 = 60 kms.