Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Linear Programming

Question:

If the objective function for a LPP is Z = 3x + 4y and the corner points of the feasible region are (0, 1), (2, 0), (5, 0), (5, 7) and (0, 4), then Max. Z - Min. Z is:

Options:

15

39

16

43

Correct Answer:

39

Explanation:

The correct answer is Option (2) → 39

$Z = 3x + 4y$

$Z(0,1) = 3(0) + 4(1) = 4$

$Z(2,0) = 6$

$Z(5,0) = 15$

$Z(5,7) = 15 + 28 = 43$

$Z(0,4) = 16$

$\text{Max } Z = 43,\ \text{Min } Z = 4$

$\text{Max } Z - \text{Min } Z = 43 - 4 = 39$

$\text{Required value} = 39$