If $ X^2 +\frac{1}{x^2} = 38 $ , then what is the value of $ X - \frac{1}{x}$ ?
Answer & explanation
Correct answer: option 1
$ X^2 +\frac{1}{x^2} = 38 $
what is the value of $ X - \frac{1}{x}$
a2 + b2 = n
a + b = \(\sqrt {n - 2}\)
$ X - \frac{1}{x}$ = \(\sqrt {38 - 2}\) = 6