The power factor of an RL circuit is $\frac{1}{2}$. If the frequency of a.c. is doubled, the power factor will be:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{1}{\sqrt{13}}$
Power factor (P.F.) = $\frac{1}{2}$
$P.F.=\frac{R}{\sqrt{R^2+{X_L}^2}}$
$⇒\frac{1}{2}=\frac{1}{\sqrt{1+\left(\frac{X_L}{R}\right)^2}}$
$⇒1+\frac{w.L}{R}=4$
$⇒\frac{w.L}{R}=3$
$∴P.F.=\frac{1}{\sqrt{1+6^2}}=\frac{1}{\sqrt{13}}$