Match List-I with List-II
|
List-I Differential Equation |
List-II Order and Degree |
|
(A) $(\frac{d^2y}{dx^2})^2-e^x(\frac{dy}{dx})^4+1=0$ |
(I) order = 1 and degree = 2 |
|
(B) $(\frac{dy}{dx})^2+xy = 0$ |
(II) order = 2 and degree = 1 |
|
(C) $(1+\frac{dy}{dx})^{3/2}=4(\frac{d^2y}{dx^2})^2$ |
(III) order 2 and degree = 2 |
|
(D) $\sqrt{\frac{d^2y}{dx^2}+1}=\frac{dy}{dx}$ |
(IV) order = 2 and degree = 4 |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (2) → (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
|
List-I Differential Equation |
List-II Order and Degree |
|
(A) $(\frac{d^2y}{dx^2})^2-e^x(\frac{dy}{dx})^4+1=0$ |
(III) order 2 and degree = 2 |
|
(B) $(\frac{dy}{dx})^2+xy = 0$ |
(I) order = 1 and degree = 2 |
|
(C) $(1+\frac{dy}{dx})^{3/2}=4(\frac{d^2y}{dx^2})^2$ |
(IV) order = 2 and degree = 4 |
|
(D) $\sqrt{\frac{d^2y}{dx^2}+1}=\frac{dy}{dx}$ |
(II) order = 2 and degree = 1 |
(A) $\left(\frac{d^2y}{dx^2}\right)^2 - e^x\left(\frac{dy}{dx}\right)^4 + 1 = 0$ Highest derivative: $\frac{d^2y}{dx^2}$ → order = 2; highest power = 2 → degree = 2 → (III)
(B) $\left(\frac{dy}{dx}\right)^2 + xy = 0$ Highest derivative: $\frac{dy}{dx}$ → order = 1; highest power = 2 → degree = 2 → (I)
(C) $\left(1+\frac{dy}{dx}\right)^{3/2} = 4\left(\frac{d^2y}{dx^2}\right)^2$ Fractional power present; remove root → square both sides: $\left(1+\frac{dy}{dx}\right)^3 = 16\left(\frac{d^2y}{dx^2}\right)^4$ → order = 2, degree = 4 → (IV)
(D) $\sqrt{\frac{d^2y}{dx^2}+1} = \frac{dy}{dx}$ Square both sides → $\frac{d^2y}{dx^2} + 1 = \left(\frac{dy}{dx}\right)^2$ → order = 2, degree = 1 → (II)
Final Matching:
(A)–(III), (B)–(I), (C)–(IV), (D)–(II)