The ratio of the quantities of acid and water in a mixture is 1 : 3. If 5 liters of acid is further added to the mixture, the new ratio becomes 1 : 2. The quantity of new mixture in liters is?

45

          A    :    W

old      1    :     3  ..........(i)

New    1    :     2  ..........(ii)

(i) × 2 and (ii) × 3 to make the quantity of water equal,

          A    :    W

old      2    :     6 

New    3    :     6

Difference of Acid in old and new ⇒ 1R = 5 (given)

Thus, Quantity of new mixture ⇒ 9R = 9 × 5 = 45