If 5x + \(\frac{1}{3x}\)= 4 find 9x2 + \(\frac{1}{{25x }^{2 }}\)
Answer & explanation
Correct answer: option 3
5x + \(\frac{1}{3x}\) = 4
Multiply by \(\frac{3}{5}\) in equation
\(\frac{3}{5}\) (5x + \(\frac{1}{3x}\)) = 4 \(\times \) \(\frac{3}{5}\)
3x + \(\frac{1}{5x}\) = \(\frac{12}{5}\)
By squaring on both sides
9x2 + \(\frac{1}{{25x }^{ 2}}\) + 2\(\times \) 3 \(\times \) \(\frac{1}{5}\) = \(\frac{144}{25}\)
9x2 + \(\frac{1}{{25x }^{ 2}}\) = \(\frac{144}{25}\) - \(\frac{6}{5}\) = \(\frac{114}{25}\)