A conical vessel, whose internal radius is 20 cm and height is 27 cm, is full of water. If this water is poured into a cylindrical vessel with internal radius 15 cm, what will be the height to which the water rises in it?

16 cm

We know that,

Volume of cone = \(\frac{1}{3}\) × πr²h

Volume of cylinder = πr²h

We have,

Internal radius of vessel = 20 cm

Height of vessel = 27 cm

Volume of conical vessel = \(\frac{1}{3}\) × π × 20² × 27

Volume of cylindrical vessel = π × 15² × height

= \(\frac{1}{3}\) × π × 20² × 27= π × 15² × height

= Height = 16 cm