A conical vessel, whose internal radius is 20 cm and height is 27 cm, is full of water. If this water is poured into a cylindrical vessel with internal radius 15 cm, what will be the height to which the water rises in it?
Answer & explanation
Correct answer: option 1
We know that,
Volume of cone = \(\frac{1}{3}\) × πr2h
Volume of cylinder = πr2h
We have,
Internal radius of vessel = 20 cm
Height of vessel = 27 cm
Volume of conical vessel = \(\frac{1}{3}\) × π × 202 × 27
Volume of cylindrical vessel = π × 152 × height
= \(\frac{1}{3}\) × π × 202 × 27= π × 152 × height
= Height = 16 cm