CUET Preparation Today
If x + y + z = 0, then the value of $\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}$ is : |
3 1 0 2 |
3 |
If x + y + z = 0 Put x = y = 1, z = -2 $\frac{1^2}{1 × -2}+\frac{1^2}{-2 × 1}+\frac{-2^2}{1 × 1}$ $\frac{1}{-2}+\frac{1}{-2}+\frac{4}{1}$ = -1 + 4 = 3 |
