Simplify the following expression. $(2x - 3y)^3 - 18 xy (2x - 3y)$ |
$8x^3 - 27y^3 - 36 x^2y- 54 xy^2$ $8x^3 - 72x^2y + 108 xy^2- 27 y^3$ $8x^3 - 27y^3$ $8x^3 + 108xy^2 - 72x^2y$ |
$8x^3 - 72x^2y + 108 xy^2- 27 y^3$ |
We have to solve $(2x - 3y)^3 - 18 xy (2x - 3y)$ Put x = y = 1, ( These value will satisfy the given equations) Value of the expression = (2 × 1 - 3 × 1)3 - 18(2 × 1 - 3 × 1) = -1 - 18(-1) = -1 + 18 = 17 If we check option (2), 8(1) - 72(1) + 108(1) - 27(1) = 116 - 99 = 17 So the answer is = $8x^3 - 72x^2y + 108 xy^2- 27 y^3$ |