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Physics
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The capacitance of a capacitor is 4 µF and it's potential is 100 V. The energy released on discharging it fully will be
0.02 J
0.04 J
0.025 J
0.05 J
$ U = \frac{1}{2}CV^2 = \frac{1}{2} \times 4\times 10^{-6} \times 100^2 = 0.02J$