Practicing Success
Practicing Success
CUET Preparation Today
The capacitance of a capacitor is 4 µF and it's potential is 100 V. The energy released on discharging it fully will be |
0.02 J 0.04 J 0.025 J 0.05 J |
0.02 J |
$ U = \frac{1}{2}CV^2 = \frac{1}{2} \times 4\times 10^{-6} \times 100^2 = 0.02J$ |
