The capacitance of a capacitor is \( 4\,\mu\mathrm{F} \) and its potential is 100 V. The energy released on discharging it fully will be
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 0.02 J
A charged capacitor stores electrostatic energy in the field between its plates. When it is discharged fully, all of this stored energy is released.
\( \displaystyle U = \frac{1}{2}\,C V^{2} \)
\( C = 4\,\mu\mathrm{F} = 4\times10^{-6}\,\mathrm{F} \)
\( V = 100\,\mathrm{V} \)
\( \displaystyle U = \frac{1}{2} \times 4\times10^{-6} \times (100)^{2} \)
\( \displaystyle U = 2\times10^{-6} \times 10^{4} = 0.02\,\mathrm{J} \)