The capacitance of a capacitor is 4 µF and it's potential is 100 V. The energy released on discharging it fully will be
Answer & explanation
Correct answer: option 1
$ U = \frac{1}{2}CV^2 = \frac{1}{2} \times 4\times 10^{-6} \times 100^2 = 0.02J$
The capacitance of a capacitor is 4 µF and it's potential is 100 V. The energy released on discharging it fully will be
Correct answer: option 1
$ U = \frac{1}{2}CV^2 = \frac{1}{2} \times 4\times 10^{-6} \times 100^2 = 0.02J$