Practicing Success
Three integers are chosen at random from the first 20 integers. The probability that their product is even is: |
2/19 3/29 17/19 4/29 |
17/19 |
For product to be even, there should be atleast one even no. amongst the three chosen numbers. Total no. of favorable groups = n(1 even, 2 odd) + n(2 even, 1 odd) + n(3 even) $={^{10}C}_1.{^{10}C}_2+{^{10}C}_2.{^{10}C}_1+{^{10}C}_3=$ |