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If sin C =$\frac{9}{10}$, then what is the value of cos2 C ? |
$\frac{19}{100}$ $\frac{81}{\sqrt{19}}$ $\frac{19}{10}$ $\frac{\sqrt{19}}{100}$ |
$\frac{19}{100}$ |
We are given that , sin C = \(\frac{9}{10}\) Now, cos² C { using , sin²x + cos²x = 1 } = ( 1 - sin²C ) = 1 - \(\frac{81}{100}\) = \(\frac{19}{100}\) |
