If x + \(\frac{1}{x}\) = 12
then find the value of (x2 + \(\frac{1}{x^2}\) + 13)
Answer & explanation
Correct answer: option 1
⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2
Here,
x + \(\frac{1}{x}\) = 12, then
⇒ ( x2 + \(\frac{1}{x^2}\) + 13 ) = 122 - 2 + 13 = 155