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If x + \(\frac{1}{x}\) = 12 then find the value of (x2 + \(\frac{1}{x^2}\) + 13) |
155 157 160 172 |
155 |
⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2 Here, x + \(\frac{1}{x}\) = 12, then ⇒ ( x2 + \(\frac{1}{x^2}\) + 13 ) = 122 - 2 + 13 = 155 |
