If x + \(\frac{1}{x}\) = 12 then find the value of  (x2 + \(\frac{1}{x^2}\) + 13)

155 157 160 172

155

⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2 Here, x + \(\frac{1}{x}\) = 12, then  ⇒ ( x2 + \(\frac{1}{x^2}\) + 13 ) = 122 - 2 + 13   = 155