CUET Preparation Today
If $tan θ +\frac{1}{tan θ} = 2, $ then what the value of $tan^2 θ +\frac{1}{tan^2θ}$ is ___________. |
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2 |
$tan θ +\frac{1}{tan θ} = 2$ { using, If x + \(\frac{1}{x}\) = a then x² + \(\frac{1}{x²}\) = a² - 2 } Now, tan²θ + \(\frac{1}{tan²θ}\) = 2² - 2 = 2 |
