Practicing Success
Practicing Success
CUET Preparation Today
If $tan θ +\frac{1}{tan θ} = 2, $ then what the value of $tan^2 θ +\frac{1}{tan^2θ}$ is ___________. |
-4 2 4 3 |
2 |
$tan θ +\frac{1}{tan θ} = 2$ { using, If x + \(\frac{1}{x}\) = a then x² + \(\frac{1}{x²}\) = a² - 2 } Now, tan²θ + \(\frac{1}{tan²θ}\) = 2² - 2 = 2 |
