If tan θ +1/(tan θ) = 2, then what the value of tan^2 θ +1/(tan^2θ) i…

$tan θ +\frac{1}{tan θ} = 2$

{ using, If  x + \(\frac{1}{x}\) = a

then  x² + \(\frac{1}{x²}\) = a² - 2 }

Now,

tan²θ + \(\frac{1}{tan²θ}\) = 2² - 2

= 2