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A coin is thrown 4 times. What is the probability of getting at least three heads? |
$\frac{1}{16}$ $\frac{1}{8}$ $\frac{5}{16}$ $\frac{1}{4}$ |
$\frac{1}{4}$ |
Possible outcomes :- ( HHHT , HHTH , HTHH, THHH ) = 4 Total number of outcomes = 2n = 24 = 16 Probability of getting atleast 3 heads = \(\frac{ 4 }{ 16 }\) = \(\frac{ 1 }{ 4 }\) |
