P is \(1\frac{3 }{7}\) times as heavy as water and water is \(1\frac{2 }{5}\) times as heavy as Q. The amount of P that must be added to 7 liters of Q so that the mixture may weigh as much as an equal volume of water will be?
Answer & explanation
Correct answer: option 3
\(1\frac{3 }{7}\) = \(\frac{10}{7}\)
\(1\frac{2}{5}\) = \(\frac{7}{5}\)
Ratio of weight :
P : W = 10 : 7
W : Q = 7 : 5
Hence, P : W : Q = 10 : 7 : 5
Now, ATQ
