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The three medians RQ, SP and TN of ΔRST intersect at point O. If the area of ΔRST is 48 cm2, then the area of the quadrilateral SQON is : |
20 cm2 12 cm2 16 cm2 18 cm2 |
16 cm2 |
We have, Area of ΔRST = 48 cm2 We know that, Area of ΔSQO = \(\frac{1}{6}\) × Area of ΔRST Area of ΔSQO = \(\frac{1}{6}\) × 48 = 8 cm2 Area of SQON = 2 × Area of ΔSQO = 2 × 8 = 16 cm2 |
