In an alloy of zinc, copper and tin in the ratio of 2 : 3 : 1 and other contains copper, tin and lead in the ratio of 5 : 4 : 3. If equal weights of both the alloys are melted together to form a third alloy, then the weight of lead per kg in the new alloy is?
Answer & explanation
Correct answer: option 2
In 1st alloy:
Zinc : Cop. : Tin
2 : 3 : 1 = 6
In 2nd alloy:
Cop. : Tin : Lead
5 : 4 : 3 = 12
(Make total of 1st and 2nd equal, multiple by 2 in 1st alloy ratio)
In 1st alloy:
Zinc : Cop. : Tin
4 : 6 : 2 = 12
In 2nd alloy:
Cop. : Tin : Lead
5 : 4 : 3 = 12
⇒
Zinc : Cop. : Tin : Lead
4 : 6 : 2
5 : 4 : 3
4 : 11 : 6 : 3 = 24 (Total After mixing)
Weight of Lead in the mixture = \(\frac{3}{24}\) = \(\frac{1}{8}\) = 0.125 Kg.