1 + 2cot2 Ø + 2cos Ø cosec2 Ø, 0° < Ø < 90°, is equal to ?
Answer & explanation
Correct answer: option 3
(1 + cot2 Ø) + cot2 Ø + 2cos Ø cosec2 Ø
⇒ cosec2 Ø + cot2 Ø + 2cot Ø cosec Ø
⇒ (cosec Ø + cot Ø)2 = (\(\frac{1}{sin Ø}\) + \(\frac{cos Ø}{sin Ø}\))
= \(\frac{(1 + cos Ø)^2}{sin^2 Ø}\)