What is the value of $\frac{tan^260°-2sin^245°}{cos24°cos37°cosec53°cos60°cosec66°+sin^260°}$
Answer & explanation
Correct answer: option 4
$\frac{tan^260°-2sin^245°}{cos24°cos37°cosec53°cos60°cosec66°+sin^260°}$
By using concept :-
cosecA = secB Iff A + B = 90°
= $\frac{(√3)²-2(1/√2)²}{cos24°cos37°sec37°.(1/2)sec24°+(√3/2)²}$
= $\frac{3-1}{(1/2)+3/4}$
= $\frac{3-1}{5/4}$
= $1\frac{3}{5}$