What is the value of $\frac{tan^260°-2sin^245°}{cos24°cos37°cosec53°cos60°cosec66°+sin^260°}$

$1\frac{3}{5}$

$\frac{tan^260°-2sin^245°}{cos24°cos37°cosec53°cos60°cosec66°+sin^260°}$

By using concept :-

cosecA = secB  Iff  A + B = 90°

= $\frac{(√3)²-2(1/√2)²}{cos24°cos37°sec37°.(1/2)sec24°+(√3/2)²}$

= $\frac{3-1}{(1/2)+3/4}$

= $\frac{3-1}{5/4}$

= $1\frac{3}{5}$