A bag contains 12 white and 18 red balls. Two balls are drawn in succession without replacement. The probability that the first is red and second is white is :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{36}{145}$
No of red balls = 8
white balls = 12
Total balls = 30
so P(first red, second white)
$=\frac{{^{18}C}_1×{^{12}C}_1}{{^{30}C}_2×2!}=\frac{18×12×2}{30×29×2}$
$⇒\frac{36}{145}$