A bag contains 12 white and 18 red balls. Two balls are drawn in succession without replacement. The probability that the first is red and second is white is :

$\frac{36}{145}$

The correct answer is Option (4) → $\frac{36}{145}$

No of red balls = 8

white balls = 12

Total balls = 30

so P(first red, second white)

$=\frac{{^{18}C}_1×{^{12}C}_1}{{^{30}C}_2×2!}=\frac{18×12×2}{30×29×2}$

$⇒\frac{36}{145}$