If $\sin (x+y)=e^{x+y}-2$, then $\frac{d y}{d x}$ is equal to
Answer & explanation
Correct answer: option 3
$\sin (x+y)=e^{x+y}-2$
differentiating wrt x
$\cos(x + y)[1+\frac{dy}{dx}]=e^{x+y}[1+\frac{dy}{dx}]$
$⇒\frac{dy}{dx}=-1$
If $\sin (x+y)=e^{x+y}-2$, then $\frac{d y}{d x}$ is equal to
Correct answer: option 3
$\sin (x+y)=e^{x+y}-2$
differentiating wrt x
$\cos(x + y)[1+\frac{dy}{dx}]=e^{x+y}[1+\frac{dy}{dx}]$
$⇒\frac{dy}{dx}=-1$