CUET Preparation Today
CUET
-- Mathematics - Section A
Definite Integration
The value of $\int\limits_0^{1} \frac{a-b x^2}{\left(a+b x^2\right)^2} d x$ is:
$\frac{a-b}{a+b}$
$\frac{1}{a-b}$
$\frac{a+b}{2}$
$\frac{1}{a+b}$
The correct answer is Option (4) → $\frac{1}{a+b}$
