If sinθ + cosec θ = 5 , find the value of sin2θ + cosec2θ .

30 27 23 25

23

Formula I → [ cosec = \(\frac{1}{sinθ}\)] Formula II → [If x + \(\frac{1}{x}\) = n and x2 + \(\frac{1}{x^2}\) = n2 - 2] sinθ + \(\frac{1}{sinθ}\) = 5 ⇒ sin2θ + \(\frac{1}{sin^2θ}\) = (5)2 - 2 ⇒ sin2θ + cosec2θ = 25 - 2 = 23