The perimeter of an isosceles triangle is 3.6 m and its base is 30 cm shorter than each of the equal sides. What is the area (in m2 ) of the triangle?
Answer & explanation
Correct answer: option 1
Given,
Perimeter of isosceles triangle = 3.6m
a = equal side and b = unequal side
Area of isosceles triangle = \(\frac{b}{2}\) × \(\sqrt {a^2 - \frac{b^2}{4}}\)
So,
= b = a - 0.3
= 3.6 = 2a + b
= 3.6 = 2a + a - 0.3
= a = 1.3 m
b = 1.3 - 0.3 = 1m
h = \(\frac{1}{2}\) × \(\sqrt {1.3^2 - \frac{1^2}{4}}\) = 0.6 m2