The perimeter of an isosceles triangle is 3.6 m and its base is 30 cm shorter than each of the equal sides. What is the area (in m² ) of the triangle?

0.6

Given,

Perimeter of isosceles triangle = 3.6m

a = equal side and b = unequal side

Area of isosceles triangle = \(\frac{b}{2}\) × \(\sqrt {a^2 - \frac{b^2}{4}}\)

So,

= b = a - 0.3

= 3.6 = 2a + b

= 3.6 = 2a + a - 0.3

= a = 1.3 m

b = 1.3 - 0.3 = 1m

h = \(\frac{1}{2}\) × \(\sqrt {1.3^2 - \frac{1^2}{4}}\) = 0.6 m²