If x + \(\frac{1}{x}\) = 17 then find the value of  x2 + \(\frac{1}{x^2}\)

142 119 289 287

287

⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2 Here, x + \(\frac{1}{x}\) = 17 , then  ⇒ x2 + \(\frac{1}{x^2}\) = 172 - 2  = 287