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If x + \(\frac{1}{x}\) = 17 then find the value of x2 + \(\frac{1}{x^2}\) |
142 119 289 287 |
287 |
⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2 Here, x + \(\frac{1}{x}\) = 17 , then ⇒ x2 + \(\frac{1}{x^2}\) = 172 - 2 = 287 |
