CUET Preparation Today
If K≡ 5 (mod 11), then all the possible non-negative values of K are : |
{2, 13, 24, 35, .......} {16, 27, 38, 49, ........} {5, 16, 27, 38, 49, ........} {4, 15, 26, 37, ........} |
{5, 16, 27, 38, 49, ........} |
The correct answer is Option (3) → {5, 16, 27, 38, 49, ........} The given modular congruence is, $k≡5(mod\,11)$ ⇒ General solution = $11n + 5$ ($n≥0$ and $n∈Z$) $∴k=\{5, 16, 27, 38, 49, ........\}$ |
